Re: exists $foo[7] and delete $foo[7]

[Bart Schuller <schuller@lunatech.com>]

On Thu, Jan 13, 2000 at 01:08:52PM -0700, Tom Christiansen wrote:
> This is nice and parallel.  splice() to an array is delete() to a
> hash.  Well, I sure thought it was.  Isn't it?  I don't really
> understand how to modify this for the proposed behaviour of delete
> $array[1].  Please help me out here.

Stop!

You can't be serious, splice changes half of your keys. There's no
equivalent with hashes.

-- 
The idea is that the first face shown to people is one they can readily
accept - a more traditional logo. The lunacy element is only revealed
subsequently, via the LunaDude. [excerpted from the Lunatech Identity Manual]

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Follow-Ups from:

Ted Ashton <ashted@southern.edu>

References to:

Tom Christiansen <tchrist@chthon.perl.com>

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