This one is sufficiently complicated that it's not obvious:
((a ∨ (a → b)) → b) → b
(∨I) 4From (3) and (1), conclude b (→E) 5From (2) and (4), conclude a → b (→I)(discharge 2) 6From (5) conclude a ∨ (a → b) (∨I) 7From (6) and (1), conclude b (→E) 8From (1) and (7), conclude (a ∨ (a → b)) → b) → b (→I) (discharge 1)
(→E) 5From (2) and (4), conclude a → b (→I)(discharge 2) 6From (5) conclude a ∨ (a → b) (∨I) 7From (6) and (1), conclude b (→E) 8From (1) and (7), conclude (a ∨ (a → b)) → b) → b (→I) (discharge 1)
(→E) 8From (1) and (7), conclude (a ∨ (a → b)) → b) → b (→I) (discharge 1)
(→I) (discharge 1)