stralloc − dynamically allocated strings |
#include <stralloc.h> int stralloc_ready(&sa,len); int
stralloc_copy(&sa,&sa2); int
stralloc_cat(&sa,&sa2); int
stralloc_append(&sa,buf); int stralloc_starts(&sa,buf); stralloc sa = {0}; |
A stralloc variable holds a string in dynamically allocated space. String length is limited only by memory. String contents are unrestricted. The stralloc structure has three components: sa.s is a pointer to the string, or 0 if it is not allocated; sa.len is the number of bytes in the string, if it is allocated; sa.a is the number of bytes allocated for the string, if it is allocated. A stralloc variable should be initialized to {0}, meaning unallocated. stralloc_ready makes sure that sa has enough space allocated for len characters. It allocates extra space if necessary. stralloc_readyplus makes sure that sa has enough space allocated for len characters more than its current length. If sa is unallocated, stralloc_readyplus is the same as stralloc_ready. stralloc_copy copies sa2 to sa, allocating space if necessary. Here sa2 is an allocated stralloc variable. stralloc_copys copies a 0-terminated string, buf, to sa, without the 0. stralloc_copyb copies len characters from buf to sa. stralloc_cat appends sa2 to sa, allocating space if necessary. If sa is unallocated, stralloc_cat is the same as stralloc_copy. stralloc_cats and stralloc_catb are analogous to stralloc_copys and stralloc_copyb. stralloc_append adds a single character, *buf, to sa, allocating space if necessary. stralloc_0 adds a single 0 character to sa. stralloc_starts returns 1 if the 0-terminated string buf, without the 0, is a prefix of sa. |
If a stralloc routine runs out of memory, it leaves sa alone and returns 0, setting errno appropriately. On success it returns 1; this guarantees that sa is allocated. |
alloc(3), error(3) |